The equation of a parabola is y=x2+2x−4. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+2x−4. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the Square:Complete the square to transform the given equation into vertex form.The given equation is y=x2+2x−4. To complete the square, we need to find a value that, when added and subtracted to the equation, forms a perfect square trinomial with x2+2x.The value needed is (2/2)2=1. We add and subtract 1 inside the equation.
Add Value Found: Add and subtract the value found in Step 2 to the equation.y=x2+2x−4y=x2+2x+1−1−4Now, group the perfect square trinomial and the constants.
Rewrite Equation: Rewrite the equation with the perfect square trinomial and combine the constants.y=(x2+2x+1)−1−4y=(x+1)2−5Now, the equation is in vertex form, where the vertex is (−1,−5).
More problems from Write a quadratic function in vertex form