The equation of a parabola is y=x2+2x−3. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+2x−3. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete square:Complete the square to rewrite the equation y=x2+2x−3 in vertex form.First, we need to complete the square for the x-terms. To do this, we take half of the coefficient of x, which is 2, divide it by 2 to get 1, and then square it to get 1. We will add and subtract this value inside the equation.
Add/subtract square: Add and subtract the square of half the coefficient of x inside the equation.The equation becomes y=x2+2x+1−1−3.We added 1 and subtracted 1 to complete the square without changing the equation's value.
Group trinomial, combine: Group the perfect square trinomial and combine the constants.The equation now is y=(x2+2x+1)−1−3.The perfect square trinomial is (x+1)2, and combining the constants −1 and −3 gives us −4.
Write in vertex form: Write the equation in vertex form.The equation in vertex form is y=(x+1)2−4.
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