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The equation of a parabola is y=x2+2x2y = x^2 + 2x - 2. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x2+2x2y = x^2 + 2x - 2. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by the equation y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the square: Complete the square to rewrite the equation y=x2+2x2y = x^2 + 2x - 2 in vertex form.\newlineFirst, we need to complete the square for the xx-terms. To do this, we take half of the coefficient of xx, which is 22, divide it by 22 to get 11, and then square it to get 11. We will add and subtract this value inside the equation.
  3. Add and subtract: Add and subtract (22)2(\frac{2}{2})^2 inside the equation.\newlineWe have y=x2+2x2y = x^2 + 2x - 2. Now we add and subtract 11 inside the equation to complete the square:\newliney=x2+2x+112y = x^2 + 2x + 1 - 1 - 2
  4. Group and combine: Group the perfect square trinomial and combine the constants.\newlineNow we group the terms to form a perfect square trinomial and combine the constants:\newliney=(x2+2x+1)3y = (x^2 + 2x + 1) - 3
  5. Factor trinomial: Factor the perfect square trinomial.\newlineThe expression x2+2x+1x^2 + 2x + 1 is a perfect square and can be factored as (x+1)2(x + 1)^2. So the equation now reads:\newliney=(x+1)23y = (x + 1)^2 - 3
  6. Write in vertex form: Write the equation in vertex form.\newlineThe equation in vertex form is now:\newliney=(x+1)23y = (x + 1)^2 - 3\newlineThis is the vertex form of the given parabola, where the vertex is (1,3)(-1, -3).

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