The equation of a parabola is y=x2+2x−2. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+2x−2. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by the equation y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the square:Complete the square to rewrite the equation y=x2+2x−2 in vertex form.First, we need to complete the square for the x-terms. To do this, we take half of the coefficient of x, which is 2, divide it by 2 to get 1, and then square it to get 1. We will add and subtract this value inside the equation.
Add and subtract: Add and subtract (22)2 inside the equation.We have y=x2+2x−2. Now we add and subtract 1 inside the equation to complete the square:y=x2+2x+1−1−2
Group and combine: Group the perfect square trinomial and combine the constants.Now we group the terms to form a perfect square trinomial and combine the constants:y=(x2+2x+1)−3
Factor trinomial: Factor the perfect square trinomial.The expression x2+2x+1 is a perfect square and can be factored as (x+1)2. So the equation now reads:y=(x+1)2−3
Write in vertex form: Write the equation in vertex form.The equation in vertex form is now:y=(x+1)2−3This is the vertex form of the given parabola, where the vertex is (−1,−3).
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