The equation of a parabola is y=x2+10x+20. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+10x+20. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the Square:Complete the square to transform the given equation into vertex form.We start with the given equation y=x2+10x+20. To complete the square, we need to find the value that makes x2+10x a perfect square trinomial. This value is (10/2)2=25. We will add and subtract 25 inside the equation.
Add and Subtract: Add and subtract 25 to the equation.y=x2+10x+25−25+20Now, we have added 25 and subtracted 25, which keeps the equation balanced.
Rewrite Equation: Rewrite the equation by grouping the perfect square trinomial and combining the constants.y=(x2+10x+25)−25+20y=(x+5)2−5We have now written the equation in vertex form, where (x+5)2 is the perfect square trinomial and −5 is the result of combining the constants.
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