The equation of a circle is (x+2)2+(y+6)2=16. What are the center and radius of the circle?Choose 1 answer:(A) The center is (2,−6) and the radius is 6 .(B) The center is (−2,6) and the radius is 6 .(C) The center is (−2,−6) and the radius is 4 .(D) The center is (1,2) and the radius is 16 .
Q. The equation of a circle is (x+2)2+(y+6)2=16. What are the center and radius of the circle?Choose 1 answer:(A) The center is (2,−6) and the radius is 6 .(B) The center is (−2,6) and the radius is 6 .(C) The center is (−2,−6) and the radius is 4 .(D) The center is (1,2) and the radius is 16 .
Circle Equation Standard Form: The equation of a circle in standard form is (x−h)2+(y−k)2=r2, where (h,k) is the center of the circle and r is the radius.
Compare with Given Equation: Given the equation of the circle is (x+2)2+(y+6)2=16, we can compare it to the standard form to find the center and the radius.
Find Center: The center of the circle is found by looking at the values that x and y are being added or subtracted by inside the parentheses. In the standard form, we subtract h from x and k from y. In our equation, we are adding 2 to x and 6 to y, which means y0 and y1. Therefore, the center is y2.
Find Radius: The radius of the circle is the square root of the value on the right side of the equation. Since the right side of the equation is 16, we take the square root of 16 to find the radius, which is 4.
Match with Options: Now we can match our findings with the given options. The center is (−2,−6) and the radius is 4, which corresponds to option (C).
More problems from Write a quadratic function from its x-intercepts and another point