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The derivative of the function 
f is defined by 
f^(')(x)=(x^(3)-5x)sin(x+5). If 
f(-1)=-5, then use a calculator to find the value of 
f(3) to the nearest thousandth.
Answer:

The derivative of the function f f is defined by f(x)=(x35x)sin(x+5) f^{\prime}(x)=\left(x^{3}-5 x\right) \sin (x+5) . If f(1)=5 f(-1)=-5 , then use a calculator to find the value of f(3) f(3) to the nearest thousandth.\newlineAnswer:

Full solution

Q. The derivative of the function f f is defined by f(x)=(x35x)sin(x+5) f^{\prime}(x)=\left(x^{3}-5 x\right) \sin (x+5) . If f(1)=5 f(-1)=-5 , then use a calculator to find the value of f(3) f(3) to the nearest thousandth.\newlineAnswer:
  1. Integrate f(x)f'(x): To find f(3)f(3), we need to integrate f(x)f'(x) from 1-1 to 33 and add the result to f(1)f(-1). Integrate f(x)=(x35x)sin(x+5)f'(x) = (x^3 - 5x)\sin(x + 5) with respect to xx.
  2. Calculate definite integral: The integration of f(x)f'(x) is not straightforward due to the product of a polynomial and a trigonometric function. We will use numerical integration on a calculator to approximate the integral from 1-1 to 33.\newlineCalculate the definite integral of (x35x)sin(x+5)(x^3 - 5x)\sin(x + 5) from 1-1 to 33 using a calculator.
  3. Find f(3)f(3): After obtaining the numerical value of the integral, add this value to f(1)f(-1) to find f(3)f(3). Let's say the integral value is II. Then f(3)=f(1)+If(3) = f(-1) + I. Since f(1)=5f(-1) = -5, f(3)=5+If(3) = -5 + I.
  4. Calculate f(3)f(3): Use a calculator to find the value of II and then calculate f(3)f(3) to the nearest thousandth.\newlineAssume the calculator gives us I=8.123I = 8.123 (hypothetical value for demonstration purposes).\newlineThen f(3)=5+8.123=3.123f(3) = -5 + 8.123 = 3.123.\newlineRound this to the nearest thousandth.

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