The derivative of the function f is defined by f′(x)=x2cos(3x). If f(6)=−6, then use a calculator to find the value of f(2) to the nearest thousandth.Answer:
Q. The derivative of the function f is defined by f′(x)=x2cos(3x). If f(6)=−6, then use a calculator to find the value of f(2) to the nearest thousandth.Answer:
Integrate f′(x) for f(x): To find the value of f(2), we need to integrate the derivative f′(x) to get the original function f(x). We will then use the initial condition f(6)=−6 to find the constant of integration.
Use Symbolic Integration: The integral of f′(x)=x2cos(3x) is a bit complex and typically requires integration by parts or a special technique. However, since we are not given the exact method for integration and are asked to use a calculator, we will assume that we can use a calculator that can handle symbolic integration.
Apply Initial Condition: Using a calculator with symbolic integration capability, we integrate f′(x) to find f(x). The antiderivative of x2cos(3x) is not straightforward, but we can write it as:f(x)=∫x2cos(3x)dx+C, where C is the constant of integration.
Calculate Definite Integral: We apply the initial condition f(6)=−6 to solve for C. We substitute x=6 into the integrated function and set it equal to −6:-6 = f(6) = \int_0^6 x^2\cos(3x) \, dx + C\.We calculate the definite integral from \$0 to 6 and then solve for C.
Find Constant C: After calculating the definite integral from 0 to 6, we find the value of C by solving the equation for C. Let's assume the calculator gives us the value of the integral, and we find C accordingly.
Evaluate f(2): Now that we have the constant C, we can find f(2) by evaluating the antiderivative at x=2 and adding the constant C: f(2)=∫02x2cos(3x)dx+C. We calculate the definite integral from 0 to 2 using the calculator and then add the constant C to find f(2).
Round to Nearest Thousandth: We round the result to the nearest thousandth as requested.
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