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The derivative of the function 
f is defined by 
f^(')(x)=x^(2)cos(3x). If 
f(6)=-6, then use a calculator to find the value of 
f(2) to the nearest thousandth.
Answer:

The derivative of the function f f is defined by f(x)=x2cos(3x) f^{\prime}(x)=x^{2} \cos (3 x) . If f(6)=6 f(6)=-6 , then use a calculator to find the value of f(2) f(2) to the nearest thousandth.\newlineAnswer:

Full solution

Q. The derivative of the function f f is defined by f(x)=x2cos(3x) f^{\prime}(x)=x^{2} \cos (3 x) . If f(6)=6 f(6)=-6 , then use a calculator to find the value of f(2) f(2) to the nearest thousandth.\newlineAnswer:
  1. Integrate f(x)f'(x) for f(x)f(x): To find the value of f(2)f(2), we need to integrate the derivative f(x)f'(x) to get the original function f(x)f(x). We will then use the initial condition f(6)=6f(6) = -6 to find the constant of integration.
  2. Use Symbolic Integration: The integral of f(x)=x2cos(3x)f'(x) = x^2\cos(3x) is a bit complex and typically requires integration by parts or a special technique. However, since we are not given the exact method for integration and are asked to use a calculator, we will assume that we can use a calculator that can handle symbolic integration.
  3. Apply Initial Condition: Using a calculator with symbolic integration capability, we integrate f(x)f'(x) to find f(x)f(x). The antiderivative of x2cos(3x)x^2\cos(3x) is not straightforward, but we can write it as:\newlinef(x)=x2cos(3x)dx+Cf(x) = \int x^2\cos(3x) \, dx + C, where CC is the constant of integration.
  4. Calculate Definite Integral: We apply the initial condition f(6)=6f(6) = -6 to solve for CC. We substitute x=6x = 6 into the integrated function and set it equal to 6-6:-6 = f(6) = \int_0^6 x^2\cos(3x) \, dx + C\.We calculate the definite integral from \$0 to 66 and then solve for CC.
  5. Find Constant CC: After calculating the definite integral from 00 to 66, we find the value of CC by solving the equation for CC. Let's assume the calculator gives us the value of the integral, and we find CC accordingly.
  6. Evaluate f(2)f(2): Now that we have the constant CC, we can find f(2)f(2) by evaluating the antiderivative at x=2x = 2 and adding the constant CC:
    f(2)=02x2cos(3x)dx+Cf(2) = \int_0^2 x^2\cos(3x) \, dx + C.
    We calculate the definite integral from 00 to 22 using the calculator and then add the constant CC to find f(2)f(2).
  7. Round to Nearest Thousandth: We round the result to the nearest thousandth as requested.

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