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The derivative of the function 
f is defined by 
f^(')(x)=(x^(2)+3)sin(2x). If 
f(4)=7, then use a calculator to find the value of 
f(-1) to the nearest thousandth.
Answer:

The derivative of the function f f is defined by f(x)=(x2+3)sin(2x) f^{\prime}(x)=\left(x^{2}+3\right) \sin (2 x) . If f(4)=7 f(4)=7 , then use a calculator to find the value of f(1) f(-1) to the nearest thousandth.\newlineAnswer:

Full solution

Q. The derivative of the function f f is defined by f(x)=(x2+3)sin(2x) f^{\prime}(x)=\left(x^{2}+3\right) \sin (2 x) . If f(4)=7 f(4)=7 , then use a calculator to find the value of f(1) f(-1) to the nearest thousandth.\newlineAnswer:
  1. Integrate f(x)f'(x): To find the value of f(1)f(-1), we need to integrate the derivative f(x)f'(x) to get the original function f(x)f(x). We will then use the initial condition f(4)=7f(4) = 7 to find the constant of integration.
  2. Use initial condition: First, we integrate f(x)=(x2+3)sin(2x)f'(x) = (x^2 + 3)\sin(2x). This requires integration by parts or a special technique since it is a product of a polynomial and a trigonometric function. However, we cannot directly integrate this without more information or a different approach because the problem asks for the value of f(1)f(-1) and not the general form of f(x)f(x).

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