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The coordinates of the point 
P are 
(1,-1) and the coordinates of point 
Q are 
(10,-1). What is the distance, in units, between the point 
P and point 
Q?
Answer: units

The coordinates of the point P P are (1,1) (1,-1) and the coordinates of point Q Q are (10,1) (10,-1) . What is the distance, in units, between the point P P and point Q? Q ? \newlineAnswer: \square units

Full solution

Q. The coordinates of the point P P are (1,1) (1,-1) and the coordinates of point Q Q are (10,1) (10,-1) . What is the distance, in units, between the point P P and point Q? Q ? \newlineAnswer: \square units
  1. Identify Coordinates: Identify the coordinates of points PP and QQ. Point PP has coordinates (1,1)(1, -1) and point QQ has coordinates (10,1)(10, -1). We can see that the yy-coordinates of both points are the same, which means that the line segment connecting PP and QQ is horizontal.
  2. Use Distance Formula: Use the distance formula for points on a horizontal line.\newlineThe distance between two points on a horizontal line is the absolute difference between their xx-coordinates. The distance formula is x2x1|x_2 - x_1|, where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of the two points.
  3. Calculate Distance: Calculate the distance using the x-coordinates of PP and QQ. Substitute x1x_1 with 11 (from point PP) and x2x_2 with 1010 (from point QQ) into the distance formula. Distance = 101=9=9|10 - 1| = |9| = 9

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