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The coordinates of the point 
P are 
(0,7) and the coordinates of point 
Q are 
(5,7). What is the distance, in units, between the point 
P and point 
Q ?
Answer: units

The coordinates of the point P P are (0,7) (0,7) and the coordinates of point Q Q are (5,7) (5,7) . What is the distance, in units, between the point P P and point Q Q ?\newlineAnswer: \square units

Full solution

Q. The coordinates of the point P P are (0,7) (0,7) and the coordinates of point Q Q are (5,7) (5,7) . What is the distance, in units, between the point P P and point Q Q ?\newlineAnswer: \square units
  1. Identify Coordinates: Identify the coordinates of points PP and QQ.\newlinePoint PP has coordinates (0,7)(0,7), and point QQ has coordinates (5,7)(5,7).
  2. Same Y-coordinate: Recognize that the points share the same yy-coordinate. Since both points have the yy-coordinate of 77, they lie on a horizontal line, and the distance between them is the difference in their xx-coordinates.
  3. Calculate X-coordinate Difference: Calculate the difference in x-coordinates.\newlineThe x-coordinate of point Q is 55 and the x-coordinate of point P is 00. The difference is 50=55 - 0 = 5.
  4. Conclude Distance: Conclude that the distance between points PP and QQ is the difference in their xx-coordinates.\newlineThe distance between points PP and QQ is 55 units.

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