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The area of a rectangle is 
x^(2)+6x-16. Its width is 
x-2. What is a simplified expression for its length?

The area of a rectangle is x2+6x16 x^{2}+6 x-16 . Its width is x2 x-2 . What is a simplified expression for its length?

Full solution

Q. The area of a rectangle is x2+6x16 x^{2}+6 x-16 . Its width is x2 x-2 . What is a simplified expression for its length?
  1. Calculate Area Divided by Width: To find the length of the rectangle, we need to divide the area by the width. The area of the rectangle is given by the expression x2+6x16x^2 + 6x - 16, and the width is given by x2x - 2.
  2. Perform Polynomial Long Division: Perform the division of the area by the width. This can be done by polynomial long division or synthetic division. We will use polynomial long division here.
  3. Set Up Division: Set up the division: x^2 + 6x - 16) \div (x - 2)\. We will divide \$x^2 by xx to get xx, and then multiply xx by x2x - 2 to subtract from the original polynomial.
  4. Subtract Result: After multiplying xx by (x2)(x - 2), we get x22xx^2 - 2x. We subtract this from x2+6xx^2 + 6x to get 8x168x - 16.
  5. Divide Again: Next, we divide 8x8x by xx to get 88, and multiply 88 by (x2)(x - 2) to subtract from 8x168x - 16.
  6. Check Remainder: After multiplying 88 by (x2)(x - 2), we get 8x168x - 16. We subtract this from 8x168x - 16 to get a remainder of 00.
  7. Finalize Length: Since the remainder is 00, the division is exact, and the quotient x+8x + 8 is the simplified expression for the length of the rectangle.

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