Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The angles of a triangle are x, y and 40^(@). The difference between the two angles x and 
y is 30^(@). Find x and y.

The angles of a triangle are x,y x, y and 40 40^{\circ} . The difference between the two angles x x and y y is 30 30^{\circ} . Find x x and y y .

Full solution

Q. The angles of a triangle are x,y x, y and 40 40^{\circ} . The difference between the two angles x x and y y is 30 30^{\circ} . Find x x and y y .
  1. Triangle Angle Sum Equation: The sum of the angles in any triangle is 180180 degrees. We can write this as an equation:\newlinex+y+40=180x + y + 40 = 180
  2. Difference Between Angles: We also know that the difference between angles xx and yy is 3030 degrees. We can express this as another equation:\newlinexy=30x - y = 30
  3. Solving System of Equations: Now we have a system of two equations with two variables:\newline11) x+y+40=180x + y + 40 = 180\newline22) xy=30x - y = 30\newlineWe can solve this system by using the substitution or elimination method. Let's use the elimination method by adding the two equations together to eliminate yy.\newline(x+y+40)+(xy)=180+30(x + y + 40) + (x - y) = 180 + 30
  4. Adding Equations: Simplifying the equation, we get: 2x+40=2102x + 40 = 210
  5. Solving for x: Now, we solve for xx by subtracting 4040 from both sides of the equation:\newline2x=210402x = 210 - 40\newline2x=1702x = 170
  6. Substitute xx to Find yy: Divide both sides by 22 to find the value of xx:
    x=1702x = \frac{170}{2}
    x=85x = 85
  7. Final Solution: Now that we have the value of xx, we can find yy by substituting xx back into one of the original equations. Let's use the second equation:\newlinexy=30x - y = 30\newline85y=3085 - y = 30
  8. Final Solution: Now that we have the value of xx, we can find yy by substituting xx back into one of the original equations. Let's use the second equation:\newlinexy=30x - y = 30\newline85y=3085 - y = 30 Solve for yy by adding yy to both sides and subtracting 3030 from both sides:\newliney=8530y = 85 - 30\newliney=55y = 55

More problems from Transformations of quadratic functions