The actual dimensions of a rectangle are 9ft by 6ft. Bob measures the sides to be 8.62ft by 5.88ft. In calculating the area, what is the relative error, to the nearest hundredth. Answer:

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The actual dimensions of a rectangle are  9ft by  6ft. Bob measures the sides to be  8.62ft by  5.88ft. In calculating the area, what is the relative error, to the nearest hundredth. Answer:

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Calculate actual area: Calculate the actual area of the rectangle using the actual dimensions. Actual area = length × width = 9ft × 6ft.Perform actual area calculation: Perform the calculation for the actual area. Actual area = 9ft × 6ft = 54ft².Calculate measured area: Calculate the measured area of the rectangle using Bob's measurements. Measured area = measured length × measured width = 8.62ft × 5.88ft.Perform measured area calculation: Perform the calculation for the measured area. Measured area = 8.62ft × 5.88ft ≈ 50.6836ft².Calculate absolute error: Calculate the absolute error by subtracting the measured area from the actual area. Absolute error = |Actual area - Measured area| = |54ft² - 50.6836ft²|.Perform absolute error calculation: Perform the calculation for the absolute error. Absolute error = |54ft² - 50.6836ft²| ≈ 3.3164ft².Calculate relative error: Calculate the relative error by dividing the absolute error by the actual area and then multiplying by 100 to get the percentage. Relative error = (Absolute error / Actual area) × 100.Perform relative error calculation: Perform the calculation for the relative error. Relative error = (3.3164ft² / 54ft²) × 100 ≈ 6.1411%.Round relative error: Round the relative error to the nearest hundredth. Relative error ≈ 6.14%.

The actual dimensions of a rectangle are $9 \mathrm{ft}$ by $6 \mathrm{ft}$ . Bob measures the sides to be $8.62 \mathrm{ft}$ by $5.88 \mathrm{ft}$ . In calculating the area, what is the relative error, to the nearest hundredth. $\newline$ Answer:

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The actual dimensions of a rectangle are 9ft 9 \mathrm{ft} 9ft by 6ft 6 \mathrm{ft} 6ft. Bob measures the sides to be 8.62ft 8.62 \mathrm{ft} 8.62ft by 5.88ft 5.88 \mathrm{ft} 5.88ft. In calculating the area, what is the relative error, to the nearest hundredth.\newlineAnswer:

The actual dimensions of a rectangle are $9 \mathrm{ft}$ by $6 \mathrm{ft}$ . Bob measures the sides to be $8.62 \mathrm{ft}$ by $5.88 \mathrm{ft}$ . In calculating the area, what is the relative error, to the nearest hundredth. $\newline$ Answer: