The actual dimensions of a rectangle are 7 in by 2in. Eric measures the sides to be 7.31 in by 1.91 in. In calculating the area, what is the relative error, to the nearest thousandth. Answer:

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The actual dimensions of a rectangle are 7 in by  2in. Eric measures the sides to be 7.31 in by 1.91 in. In calculating the area, what is the relative error, to the nearest thousandth. Answer:

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Calculate Actual Area: First, calculate the actual area of the rectangle using the actual dimensions. Actual area = Length × Width Actual area = 7 in × 2 in Actual area = 14 in²Calculate Measured Area: Next, calculate the measured area of the rectangle using the measured dimensions. Measured area = Measured Length × Measured Width Measured area = 7.31 in × 1.91 in Measured area = 13.9611 in²Find Absolute Error: Now, find the absolute error by subtracting the actual area from the measured area. Absolute error = |Measured area - Actual area| Absolute error = |13.9611 in² - 14 in²| Absolute error = |-0.0389 in²| Absolute error = 0.0389 in² (since error is always positive)Find Relative Error: To find the relative error, divide the absolute error by the actual area and express it as a percentage. Relative error = (Absolute error / Actual area) × 100% Relative error = (0.0389 in² / 14 in²) × 100% Relative error = 0.00277857143 × 100% Relative error = 0.277857143%Round Relative Error: Round the relative error to the nearest thousandth. Relative error ≈ 0.278%

The actual dimensions of a rectangle are $7$ in by $2 \mathrm{in}$ . Eric measures the sides to be $7$ . $31$ in by $1$ . $91$ in. In calculating the area, what is the relative error, to the nearest thousandth. $\newline$ Answer:

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The actual dimensions of a rectangle are $7$ in by $2 \mathrm{in}$ . Eric measures the sides to be $7$ . $31$ in by $1$ . $91$ in. In calculating the area, what is the relative error, to the nearest thousandth. $\newline$ Answer: