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The actual dimensions of a rectangle are 6 in by 10 in. Eric measures the sides to be 5.85 in by 10 in. In calculating the area, what is the relative error, to the nearest thousandth.
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The actual dimensions of a rectangle are 66 in by 1010 in. Eric measures the sides to be 55.8585 in by 1010 in. In calculating the area, what is the relative error, to the nearest thousandth.\newlineAnswer:

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Q. The actual dimensions of a rectangle are 66 in by 1010 in. Eric measures the sides to be 55.8585 in by 1010 in. In calculating the area, what is the relative error, to the nearest thousandth.\newlineAnswer:
  1. Calculate Actual Area: To find the relative error, we first need to calculate the actual area and the measured area of the rectangle.\newlineThe actual area AactualA_{\text{actual}} is found by multiplying the actual length and width.\newlineAactual=Actual length×Actual widthA_{\text{actual}} = \text{Actual length} \times \text{Actual width}\newlineAactual=6in×10inA_{\text{actual}} = 6 \, \text{in} \times 10 \, \text{in}\newlineAactual=60in2A_{\text{actual}} = 60 \, \text{in}^2
  2. Calculate Measured Area: Now, we calculate the measured area (AmeasuredA_{\text{measured}}) using the measured dimensions.\newlineAmeasured=Measured length×Measured widthA_{\text{measured}} = \text{Measured length} \times \text{Measured width}\newlineAmeasured=5.85in×10inA_{\text{measured}} = 5.85 \, \text{in} \times 10 \, \text{in}\newlineAmeasured=58.5in2A_{\text{measured}} = 58.5 \, \text{in}^2
  3. Calculate Relative Error: The relative error ErelativeE_{\text{relative}} is the absolute value of the difference between the actual area and the measured area, divided by the actual area.\newlineErelative=AactualAmeasuredAactualE_{\text{relative}} = \frac{|A_{\text{actual}} - A_{\text{measured}}|}{A_{\text{actual}}}\newlineErelative=60 in258.5 in260 in2E_{\text{relative}} = \frac{|60 \text{ in}^2 - 58.5 \text{ in}^2|}{60 \text{ in}^2}\newlineErelative=1.5 in260 in2E_{\text{relative}} = \frac{|1.5 \text{ in}^2|}{60 \text{ in}^2}\newlineErelative=1.5 in260 in2E_{\text{relative}} = \frac{1.5 \text{ in}^2}{60 \text{ in}^2}\newlineErelative=0.025E_{\text{relative}} = 0.025
  4. Express Relative Error: To express the relative error to the nearest thousandth, we keep three decimal places. Erelative0.025E_{\text{relative}} \approx 0.025 (to the nearest thousandth)

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