The actual dimensions of a rectangle are 4ft by 2ft. David measures the sides to be 3.66ft by 1.79ft. In calculating the area, what is the relative error, to the nearest hundredth. Answer:

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The actual dimensions of a rectangle are  4ft by  2ft. David measures the sides to be  3.66ft by  1.79ft. In calculating the area, what is the relative error, to the nearest hundredth. Answer:

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Calculate Actual Area: Calculate the actual area of the rectangle using the actual dimensions. The formula for the area of a rectangle is length × width. Actual area = 4ft × 2ft = 8ft².Calculate Measured Area: Calculate the measured area of the rectangle using the measured dimensions. Measured area = 3.66ft × 1.79ft. Let's perform the multiplication to find the measured area. Measured area = 6.5502ft².Calculate Absolute Error: Calculate the absolute error by subtracting the actual area from the measured area. Absolute error = |Measured area - Actual area|. Absolute error = |6.5502ft² - 8ft²|. Absolute error = |-1.4498ft²|. Since we are looking for the absolute value, we take the positive value of the result. Absolute error = 1.4498ft².Calculate Relative Error: Calculate the relative error by dividing the absolute error by the actual area. Relative error = Absolute error / Actual area. Relative error = 1.4498ft² / 8ft². Let's perform the division to find the relative error. Relative error = 0.181225.Convert to Percentage: Convert the relative error to a percentage and round to the nearest hundredth. Relative error (as a percentage) = Relative error × 100. Relative error (as a percentage) = 0.181225 × 100. Relative error (as a percentage) = 18.1225%. Rounded to the nearest hundredth, the relative error is 18.12%.

The actual dimensions of a rectangle are $4 \mathrm{ft}$ by $2 \mathrm{ft}$ . David measures the sides to be $3.66 \mathrm{ft}$ by $1.79 \mathrm{ft}$ . In calculating the area, what is the relative error, to the nearest hundredth. $\newline$ Answer:

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The actual dimensions of a rectangle are 4ft 4 \mathrm{ft} 4ft by 2ft 2 \mathrm{ft} 2ft. David measures the sides to be 3.66ft 3.66 \mathrm{ft} 3.66ft by 1.79ft 1.79 \mathrm{ft} 1.79ft. In calculating the area, what is the relative error, to the nearest hundredth.\newlineAnswer:

The actual dimensions of a rectangle are $4 \mathrm{ft}$ by $2 \mathrm{ft}$ . David measures the sides to be $3.66 \mathrm{ft}$ by $1.79 \mathrm{ft}$ . In calculating the area, what is the relative error, to the nearest hundredth. $\newline$ Answer: