The actual dimensions of a rectangle are 4 in by 9 in. Eric measures the sides to be 3.87 in by 9.22 in. In calculating the area, what is the relative error, to the nearest thousandth. Answer:

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Calculate Actual Area: First, calculate the actual area of the rectangle using the actual dimensions. Actual area = length × width Actual area = 4 in × 9 in Actual area = 36 in²Calculate Measured Area: Next, calculate the measured area of the rectangle using the measured dimensions. Measured area = measured length × measured width Measured area = 3.87 in × 9.22 in Measured area = 35.6824 in²Find Absolute Error: Now, find the absolute error by subtracting the actual area from the measured area. Absolute error = |Measured area - Actual area| Absolute error = |35.6824 in² - 36 in²| Absolute error = | -0.3176 in²| Absolute error = 0.3176 in² (since absolute error is always positive)Calculate Relative Error: To find the relative error, divide the absolute error by the actual area and express it as a percentage. Relative error = (Absolute error / Actual area) × 100% Relative error = (0.3176 in² / 36 in²) × 100% Relative error = 0.00882222222... × 100% Relative error = 0.882222222...%Round Relative Error: Finally, round the relative error to the nearest thousandth. Relative error ≈ 0.882%

The actual dimensions of a rectangle are $4$ in by $9$ in. Eric measures the sides to be $3$ . $87$ in by $9$ . $22$ in. In calculating the area, what is the relative error, to the nearest thousandth. $\newline$ Answer:

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The actual dimensions of a rectangle are $4$ in by $9$ in. Eric measures the sides to be $3$ . $87$ in by $9$ . $22$ in. In calculating the area, what is the relative error, to the nearest thousandth. $\newline$ Answer: