How many real solutions does the equation have? f^(2)-52=-70 (A) no real solution (B) one real solution (C) two real solutions

Simplify Equation: Write down the given equation and simplify it by adding 52 to both sides to isolate the f^2 term. f^2 - 52 = -70 f^2 = -70 + 52 f^2 = -18Identify Real Solutions: Observe that f^2 is equal to a negative number (-18). Since the square of a real number cannot be negative, the equation f^2 = -18 does not have any real solutions.Conclude No Real Solutions: Conclude that the equation f^2 - 52 = -70 has no real solutions because the square of a real number cannot be negative.

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Algebra 1

Factor quadratics with leading coefficient 1

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Q. How many real solutions does the equation have?

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f^{2}-52=-70

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(A) no real solution

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(B) one real solution

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Simplify Equation: Write down the given equation and simplify it by adding $52$ to both sides to isolate the $f^2$ term. $\newline$ $f^2 - 52 = -70$ $\newline$ $f^2 = -70 + 52$ $\newline$ $f^2 = -18$
Identify Real Solutions: Observe that $f^2$ is equal to a negative number ( $-18$ ). Since the square of a real number cannot be negative, the equation $f^2 = -18$ does not have any real solutions.
Conclude No Real Solutions: Conclude that the equation $f^2 - 52 = -70$ has no real solutions because the square of a real number cannot be negative.