What can the maximum number of digits be in the repeating block of digits in the decimal expansion of 171 ? Perform the division to check your answer.
Q. What can the maximum number of digits be in the repeating block of digits in the decimal expansion of 171 ? Perform the division to check your answer.
Perform Long Division: To determine the maximum number of digits in the repeating block of the decimal expansion of 171, we need to perform the long division of 1 by 17.
Determine Fits into 100: We start the division by determining how many times 17 fits into 100 (since 17 does not fit into 1, we add a decimal point and a zero to 1, making it 10.0, and then another zero, making it 100).17 goes into 100 a total of 5 times (1000), leaving a remainder of 1001.
Calculate Remainder 15: We bring down another zero to the remainder, making it 150, and divide again by 17. 17 goes into 150 a total of 8 times (17×8=136), leaving a remainder of 14.
Divide by 17 Again: We bring down another zero to the remainder, making it 140, and divide again by 17. 17 goes into 140 a total of 8 times (17×8=136), leaving a remainder of 4.
Repeat Remainders: We bring down another zero to the remainder, making it 40, and divide again by 17. 17 goes into 40 a total of 2 times (17×2=34), leaving a remainder of 6.
Identify Repeating Block: We bring down another zero to the remainder, making it 60, and divide again by 17. 17 goes into 60 a total of 3 times (17×3=51), leaving a remainder of 9.
Identify Repeating Block: We bring down another zero to the remainder, making it 60, and divide again by 17. 17 goes into 60 a total of 3 times (17×3=51), leaving a remainder of 9.We bring down another zero to the remainder, making it 90, and divide again by 17. 17 goes into 90 a total of 171 times (172), leaving a remainder of 171.
Identify Repeating Block: We bring down another zero to the remainder, making it 60, and divide again by 17. 17 goes into 60 a total of 3 times (17×3=51), leaving a remainder of 9.We bring down another zero to the remainder, making it 90, and divide again by 17. 17 goes into 90 a total of 171 times (172), leaving a remainder of 171.We notice that we have seen the remainder 171 before, which means the digits will start to repeat from this point. The remainders we have seen so far are 175, 176, 177, 178, and 9, which correspond to the digits 171, 171, 171, 173, and 3 in the decimal expansion.
Identify Repeating Block: We bring down another zero to the remainder, making it 60, and divide again by 17. 17 goes into 60 a total of 3 times (17×3=51), leaving a remainder of 9.We bring down another zero to the remainder, making it 90, and divide again by 17. 17 goes into 90 a total of 171 times (172), leaving a remainder of 171.We notice that we have seen the remainder 171 before, which means the digits will start to repeat from this point. The remainders we have seen so far are 175, 176, 177, 178, and 9, which correspond to the digits 171, 171, 171, 173, and 3 in the decimal expansion.Since the remainders are starting to repeat, we have found the repeating block of the decimal expansion of 175. The repeating block is 176, which has 177 digits.