Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Target heart rate is determined by multiplying the reserve heart rate by training intensity level, 
p, where 
0 <= p <= 1, and adding the resting heart rate. An adult woman with a resting heart rate of 65 beats per minute (bpm) and a reserve heart rate of 
125bpm is told by a trainer that her target heart rate should not exceed 
140bpm. What is the maximum training intensity level, 
p, that is consistent with her trainer's advice?

Target heart rate is determined by multiplying the reserve heart rate by training intensity level, p p , where 0p1 0 \leq p \leq 1 , and adding the resting heart rate. An adult woman with a resting heart rate of 65 65 beats per minute (bpm \text{bpm} ) and a reserve heart rate of 125bpm 125\text{bpm} is told by a trainer that her target heart rate should not exceed 140bpm 140\text{bpm} . What is the maximum training intensity level, p p , that is consistent with her trainer's advice?

Full solution

Q. Target heart rate is determined by multiplying the reserve heart rate by training intensity level, p p , where 0p1 0 \leq p \leq 1 , and adding the resting heart rate. An adult woman with a resting heart rate of 65 65 beats per minute (bpm \text{bpm} ) and a reserve heart rate of 125bpm 125\text{bpm} is told by a trainer that her target heart rate should not exceed 140bpm 140\text{bpm} . What is the maximum training intensity level, p p , that is consistent with her trainer's advice?
  1. Identify Values: Identify the given values.\newlineResting heart rate (RHR): 6565 bpm\newlineReserve heart rate (ResHR): 125125 bpm\newlineTrainer's advice for maximum target heart rate (MaxTHR): 140140 bpm\newlineWe need to find the maximum training intensity level, pp.
  2. Write Formula: Write down the formula for the target heart rate (THR).\newlineTHR=(ResHR×p)+RHRTHR = (ResHR \times p) + RHR\newlineWe know the THR should not exceed 140140 bpm, so we set the formula equal to 140140 bpm.\newline140=(125×p)+65140 = (125 \times p) + 65
  3. Solve for pp: Solve for pp.\newlineSubtract the resting heart rate from both sides of the equation.\newline14065=125×p140 - 65 = 125 \times p\newline75=125×p75 = 125 \times p
  4. Divide to Isolate pp: Divide both sides of the equation by 125125 to isolate pp.
    p=75125p = \frac{75}{125}
    p=0.6p = 0.6

More problems from Interpreting Linear Expressions