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T_(n)=T_(1)+(n-1)f+((n-1)(n-2))/(2)s

Tn=T1+(n−1)f+(n−1)(n−2)2s T_{n}=T_{1}+(n-1) f+\frac{(n-1)(n-2)}{2} s

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Full solution

Q. Tn=T1+(n−1)f+(n−1)(n−2)2s T_{n}=T_{1}+(n-1) f+\frac{(n-1)(n-2)}{2} s
  1. Calculate TnT_n: Calculate the value of TnT_n using the formula Tn=T1+(n−1)f+(n−1)(n−2)2sT_n = T_1 + (n-1)f + \frac{(n-1)(n-2)}{2}s.
    - Plug in the values: T1=3T_1 = 3, n=5n = 5, f=2f = 2, s=1s = 1.
    - T5=3+(5−1)2+(5−1)(5−2)2⋅1T_5 = 3 + (5-1)2 + \frac{(5-1)(5-2)}{2 \cdot 1}.
    - Calculation: T5=3+8+6=17T_5 = 3 + 8 + 6 = 17.

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