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k=1(sin100)k\sum_{k=1}^{\infty}(\sin 100)^{k}

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Q. k=1(sin100)k\sum_{k=1}^{\infty}(\sin 100)^{k}
  1. Recognize Geometric Series: We recognize that the series is a geometric series with the first term a=sin(100)a = \sin(100) and the common ratio r=sin(100)r = \sin(100). The sum of an infinite geometric series can be found using the formula S=a1rS = \frac{a}{1 - r}, where |r| < 1.
  2. Check Common Ratio: First, we need to check if the common ratio r=sin(100)r = \sin(100) satisfies the condition |r| < 1. Since the sine function always returns a value between 1-1 and 11 for any angle, we have |\sin(100)| < 1.
  3. Apply Formula for Sum: Now we can apply the formula for the sum of an infinite geometric series: S=a1rS = \frac{a}{1 - r}. Here, a=sin(100)a = \sin(100) and r=sin(100)r = \sin(100), so S=sin(100)1sin(100)S = \frac{\sin(100)}{1 - \sin(100)}.
  4. Perform Calculation: We perform the calculation: S=sin(100)1sin(100)S = \frac{\sin(100)}{1 - \sin(100)}. Note that sin(100)\sin(100) is in degrees, and we should convert it to radians if we are using a calculator that requires radians. However, since we are not actually calculating the numerical value of sin(100)\sin(100), we can leave it as is.
  5. Final Answer: The final answer is S=sin(100)1sin(100)S = \frac{\sin(100)}{1 - \sin(100)}. This is the sum of the infinite series.

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