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sum_(i=4)^(7)i^(2)

i=47i2 \sum_{i=4}^{7} i^{2}

Full solution

Q. i=47i2 \sum_{i=4}^{7} i^{2}
  1. Calculate Square of 44: To solve the problem, we need to calculate the sum of the squares of each integer from 44 to 77. This means we will calculate 424^2, 525^2, 626^2, and 727^2 and then add them together.
  2. Calculate Square of 55: Calculate the square of 44: 42=164^2 = 16.
  3. Calculate Square of 66: Calculate the square of 55: 52=255^2 = 25.
  4. Calculate Square of 77: Calculate the square of 66: 62=366^2 = 36.
  5. Add Squares Together: Calculate the square of 77: 72=497^2 = 49.
  6. Perform Addition: Add all the squares together: 16+25+36+4916 + 25 + 36 + 49.
  7. Perform Addition: Add all the squares together: 16+25+36+4916 + 25 + 36 + 49. Perform the addition: 16+25=4116 + 25 = 41, 41+36=7741 + 36 = 77, 77+49=12677 + 49 = 126.

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