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Subtract. The numerator should be expanded and simplified. The denominator should be either expanded or factored. (3)/(x^(2)-49)-(9)/(x^(2)-(x)/(=))=

Subtract.\newlineThe numerator should be expanded and simplified. The denominator should be either expanded or factored.\newline3x2−49−9x2−14x+49= \frac{3}{x^{2}-49}-\frac{9}{x^{2}-14 x+49}=

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Factor sums and differences of cubesright chevron icon

Full solution

Q. Subtract.\newlineThe numerator should be expanded and simplified. The denominator should be either expanded or factored.\newline3x2−49−9x2−14x+49= \frac{3}{x^{2}-49}-\frac{9}{x^{2}-14 x+49}=
  1. Identify and Correct Error: First, we need to identify and correct the error in the second denominator. The expression (x2−(x/))(x^2-(x/)) is not complete or correct. It seems there is a typo or missing term. To proceed with the problem, we need a correct expression. Assuming the intended expression was (x2−x)(x^2-x), we can rewrite the problem as:\newline(3)/(x2−49)−(9)/(x2−x)(3)/(x^2-49) - (9)/(x^2-x)

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