Subtract. The numerator should be expanded and simplified. The denominator should be either expanded or factored. (8x)/(x^(2)+8x+16)-(6)/(x^(2)+4x)=

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Subtract. The numerator should be expanded and simplified. The denominator should be either expanded or factored.  (8x)/(x^(2)+8x+16)-(6)/(x^(2)+4x)=

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Identify denominators: First, let's identify the denominators in the given expression. We have two fractions with different denominators: x^2 + 8x + 16 and x^2 + 4x. To subtract these fractions, we need a common denominator.Factor denominators: The denominator x^2 + 8x + 16 is a perfect square trinomial, which factors to (x + 4)^2. The denominator x^2 + 4x can be factored by taking out the common factor x, resulting in x(x + 4).Find common denominator: Now, we need to find a common denominator for the two fractions. The least common denominator (LCD) is x(x + 4)(x + 4), which is the same as x(x + 4)^2.Rewrite fractions: Next, we will rewrite each fraction with the common denominator. The first fraction already has the denominator (x + 4)^2, so we only need to adjust the second fraction by multiplying the numerator and denominator by (x + 4) to have the common denominator.Subtract fractions: After adjusting the second fraction, we have: (8x)/(x + 4)^2 - (6 * (x + 4))/(x(x + 4)^2)Expand numerator: Now, we can subtract the fractions since they have the same denominator: (8x - 6 * (x + 4))/(x(x + 4)^2)Simplify expression: We expand the numerator to simplify the expression: 8x - 6x - 24 = 2x - 24Factor numerator: The simplified form of the expression is: (2x - 24)/(x(x + 4)^2)Final result: Finally, we check if the numerator can be factored further. Since 2 is a common factor of both terms in the numerator, we can factor it out: 2(x - 12)/(x(x + 4)^2)

Subtract. $\newline$ The numerator should be expanded and simplified. The denominator should be either expanded or factored. $\newline$ $\frac{8 x}{x^{2}+8 x+16}-\frac{6}{x^{2}+4 x}=$

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Subtract.\newlineThe numerator should be expanded and simplified. The denominator should be either expanded or factored.\newline8xx2+8x+16−6x2+4x= \frac{8 x}{x^{2}+8 x+16}-\frac{6}{x^{2}+4 x}= x2+8x+168x​−x2+4x6​=

Subtract. $\newline$ The numerator should be expanded and simplified. The denominator should be either expanded or factored. $\newline$ $\frac{8 x}{x^{2}+8 x+16}-\frac{6}{x^{2}+4 x}=$