Subtract. The numerator should be expanded and simplified. The denominator should be either expanded or factored. (2x)/(x^(2)-3x-18)-(5)/(x^(2)+6x+9)=

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Subtract. The numerator should be expanded and simplified. The denominator should be either expanded or factored.  (2x)/(x^(2)-3x-18)-(5)/(x^(2)+6x+9)=

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Factor the denominators: First, we need to factor the denominators of both fractions to see if they can be simplified or if there are any common factors. The first denominator is x^2 - 3x - 18. We look for two numbers that multiply to -18 and add to -3. These numbers are -6 and +3. So, x^2 - 3x - 18 factors to (x - 6)(x + 3).Factor the first denominator: The second denominator is x^2 + 6x + 9. We look for two numbers that multiply to 9 and add to 6. These numbers are +3 and +3. So, x^2 + 6x + 9 factors to (x + 3)(x + 3) or (x + 3)^2.Factor the second denominator: Now we rewrite the original expression with the factored denominators: (2x)/((x - 6)(x + 3)) - (5)/((x + 3)^2).Rewrite the expression with factored denominators: To subtract these fractions, we need a common denominator. The least common denominator (LCD) is (x - 6)(x + 3)^2. We need to multiply the numerator and denominator of the first fraction by (x + 3) to have the LCD as the denominator.Find the least common denominator: After multiplying, the first fraction becomes (2x * (x + 3))/((x - 6)(x + 3)^2). We expand the numerator: 2x * (x + 3) = 2x^2 + 6x. So the first fraction is now (2x^2 + 6x)/((x - 6)(x + 3)^2).Multiply the numerator and denominator of the first fraction: The second fraction already has (x + 3)^2 in the denominator, so we only need to multiply the numerator and denominator by (x - 6) to have the LCD as the denominator.Expand the numerator of the first fraction: After multiplying, the second fraction becomes (5 * (x - 6))/((x + 3)^2 * (x - 6)). We expand the numerator: 5 * (x - 6) = 5x - 30. So the second fraction is now (5x - 30)/((x + 3)^2 * (x - 6)).Multiply the numerator and denominator of the second fraction: Now we can subtract the two fractions since they have the same denominator: (2x^2 + 6x)/((x - 6)(x + 3)^2) - (5x - 30)/((x - 6)(x + 3)^2).Expand the numerator of the second fraction: Subtracting the numerators gives us: (2x^2 + 6x) - (5x - 30). We distribute the negative sign through the second expression: -5x + 30. Now we combine like terms: 2x^2 + 6x - 5x + 30.Subtract the two fractions: Combining like terms, we get: 2x^2 + x + 30. So the combined numerator is 2x^2 + x + 30.Subtract the numerators: The final simplified expression is: (2x^2 + x + 30)/((x - 6)(x + 3)^2).

Subtract. $\newline$ The numerator should be expanded and simplified. The denominator should be either expanded or factored. $\newline$ $\frac{2 x}{x^{2}-3 x-18}-\frac{5}{x^{2}+6 x+9}=$

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Subtract.\newlineThe numerator should be expanded and simplified. The denominator should be either expanded or factored.\newline2xx2−3x−18−5x2+6x+9= \frac{2 x}{x^{2}-3 x-18}-\frac{5}{x^{2}+6 x+9}= x2−3x−182x​−x2+6x+95​=

Subtract. $\newline$ The numerator should be expanded and simplified. The denominator should be either expanded or factored. $\newline$ $\frac{2 x}{x^{2}-3 x-18}-\frac{5}{x^{2}+6 x+9}=$