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Subtract. The numerator should be expanded and simplified. The denominator should be either expanded or factored. (9)/(x^(2)-8x-9)-(2)/(x^(2)-""⧸""=)=

Subtract.\newlineThe numerator should be expanded and simplified. The denominator should be either expanded or factored.\newline9x2−8x−9−2x2−81= \frac{9}{x^{2}-8 x-9}-\frac{2}{x^{2}-81}=

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Full solution

Q. Subtract.\newlineThe numerator should be expanded and simplified. The denominator should be either expanded or factored.\newline9x2−8x−9−2x2−81= \frac{9}{x^{2}-8 x-9}-\frac{2}{x^{2}-81}=
  1. Factor the first fraction denominator: First, we need to factor the denominators of both fractions to identify common factors and simplify the expression.\newlineThe denominator of the first fraction is x2−8x−9x^2 - 8x - 9. We look for two numbers that multiply to −9-9 and add to −8-8. The numbers −9-9 and +1+1 fit this requirement.\newlineSo, we can factor the denominator as (x−9)(x+1)(x - 9)(x + 1).
  2. Factor the second fraction denominator: The denominator of the second fraction is x2x^2 with a division symbol, which seems to be a typographical error. We cannot proceed with the problem as given because the denominator of the second fraction is incomplete.

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