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Subtract 
7x-5y+z from the product of 4 and 
(1)/(4)y-(1)/(2)x+3z

Subtract 7x5y+z 7 x-5 y+z from the product of 44 and 14y12x+3z \frac{1}{4} y-\frac{1}{2} x+3 z

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Q. Subtract 7x5y+z 7 x-5 y+z from the product of 44 and 14y12x+3z \frac{1}{4} y-\frac{1}{2} x+3 z
  1. Find Product Calculation: First, we need to find the product of 44 and the expression (14y12x+3z)(\frac{1}{4}y - \frac{1}{2}x + 3z).\newlineCalculation: 4×(14y12x+3z)4 \times (\frac{1}{4}y - \frac{1}{2}x + 3z)\newline= 4×(14y)4×(12x)+4×3z4 \times (\frac{1}{4}y) - 4 \times (\frac{1}{2}x) + 4 \times 3z\newline= y2x+12zy - 2x + 12z
  2. Subtract Expression Calculation: Now, we have to subtract the expression 7x5y+z7x - 5y + z from the result we just found.\newlineCalculation: (y2x+12z)(7x5y+z)(y - 2x + 12z) - (7x - 5y + z)\newline= y2x+12z7x+5yzy - 2x + 12z - 7x + 5y - z
  3. Combine Like Terms Calculation: Next, we combine like terms to simplify the expression.\newlineCalculation: y2x+12z7x+5yzy - 2x + 12z - 7x + 5y - z\newline= (y+5y)+(2x7x)+(12zz)(y + 5y) + (-2x - 7x) + (12z - z)\newline= 6y9x+11z6y - 9x + 11z

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