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Stephen read 12 books, 20 magazines, and 17 newspaper articles last year.
Based on this data, what is a reasonable estimate of the probability that Stephen's next reading material is a magazine? Choose the best answer.
Choose 1 answer:
(A) 0.20
(B) 0.24
(c) 0.35
(D) 0.41

Stephen read 1212 books, 2020 magazines, and 1717 newspaper articles last year.\newlineBased on this data, what is a reasonable estimate of the probability that Stephen's next reading material is a magazine? Choose the best answer.\newlineChoose 11 answer:\newline(A) 00.2020\newline(B) 00.2424\newline(C) 00.3535\newline(D) 00.4141

Full solution

Q. Stephen read 1212 books, 2020 magazines, and 1717 newspaper articles last year.\newlineBased on this data, what is a reasonable estimate of the probability that Stephen's next reading material is a magazine? Choose the best answer.\newlineChoose 11 answer:\newline(A) 00.2020\newline(B) 00.2424\newline(C) 00.3535\newline(D) 00.4141
  1. Calculate Total Reading Materials: First, we need to calculate the total number of reading materials Stephen read last year. This is the sum of books, magazines, and newspaper articles.\newlineTotal reading materials == Number of books ++ Number of magazines ++ Number of newspaper articles\newlineTotal reading materials =12+20+17= 12 + 20 + 17\newlineTotal reading materials =49= 49
  2. Find Probability of Magazine: Next, we need to find the probability that Stephen's next reading material is a magazine. The probability is the number of magazines divided by the total number of reading materials.\newlineProbability of a magazine =Number of magazinesTotal reading materials= \frac{\text{Number of magazines}}{\text{Total reading materials}}\newlineProbability of a magazine =2049= \frac{20}{49}
  3. Simplify Fraction: Now, we simplify the fraction to get a decimal that we can compare with the given options.\newlineProbability of a magazine 0.4081632653\approx 0.4081632653
  4. Round Decimal: We round the decimal to two places to match the format of the given options.\newlineRounded probability 0.41\approx 0.41

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