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Solve for x.
sqrt((x-5)^(2))=sqrt18

Solve for xx.\newline(x5)2=18 \sqrt{(x-5)^{2}}=\sqrt{18}

Full solution

Q. Solve for xx.\newline(x5)2=18 \sqrt{(x-5)^{2}}=\sqrt{18}
  1. Recognize Simplification: We start by recognizing that the square root of a square cancels out, so we can simplify (x5)2\sqrt{(x-5)^{2}} to x5|x-5|. This is because the square root and square are inverse operations, but we must consider that the square root function outputs the non-negative root, hence the absolute value.\newlineCalculation: (x5)2=x5\sqrt{(x-5)^{2}} = |x-5|
  2. Set Absolute Value: Next, we set the absolute value of x5x-5 equal to the square root of 1818, which gives us two possible equations: x5=18x-5 = \sqrt{18} or x5=18x-5 = -\sqrt{18}. This is because the absolute value of a number can be either positive or negative.\newlineCalculation: x5=18|x-5| = \sqrt{18} leads to x5=18x-5 = \sqrt{18} or x5=18x-5 = -\sqrt{18}
  3. Solve for x (11st Equation): We solve the first equation x5=18x-5 = \sqrt{18}. To find x, we add 55 to both sides of the equation.\newlineCalculation: x=18+5x = \sqrt{18} + 5
  4. Solve for x (22nd Equation): We solve the second equation x5=18x-5 = -\sqrt{18}. Similarly, we add 55 to both sides of this equation as well.\newlineCalculation: x=18+5x = -\sqrt{18} + 5
  5. Simplify 18\sqrt{18}: Now we simplify 18\sqrt{18}. The prime factorization of 1818 is 2×322 \times 3^2. We can take the square root of 323^2 out of the square root, which gives us 33.\newlineCalculation: 18=2×32=3×2\sqrt{18} = \sqrt{2 \times 3^2} = 3 \times \sqrt{2}
  6. Substitute Simplified Form: We substitute the simplified form of 18\sqrt{18} back into the equations for xx.\newlineCalculation: x=3×2+5x = 3 \times \sqrt{2} + 5 and x=3×2+5x = -3 \times \sqrt{2} + 5
  7. Final Solutions: We now have two possible solutions for xx, which are x=3×2+5x = 3 \times \sqrt{2} + 5 and x=3×2+5x = -3 \times \sqrt{2} + 5.

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