Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Sophia is saving money and plans on making monthly contributions into an account earning an annual interest rate of 
6.3% compounded monthly. If Sophia would like to end up with 
$65,000 after 11 years, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Sophia is saving money and plans on making monthly contributions into an account earning an annual interest rate of 6.3% 6.3 \% compounded monthly. If Sophia would like to end up with $65,000 \$ 65,000 after 1111 years, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Sophia is saving money and plans on making monthly contributions into an account earning an annual interest rate of 6.3% 6.3 \% compounded monthly. If Sophia would like to end up with $65,000 \$ 65,000 after 1111 years, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineAA (future value of the account) = $65,000\$65,000\newlineii (monthly interest rate) = 6.3%6.3\% annual interest rate / 1212 months = 0.063/120.063 / 12\newlinenn (total number of periods) = 1111 years * 1212 months/year
  2. Convert Annual Interest Rate: Convert the annual interest rate to a monthly interest rate. \newlinei=0.06312i = \frac{0.063}{12}\newlinei=0.00525i = 0.00525 (monthly interest rate)
  3. Calculate Total Periods: Calculate the total number of periods (months) over 1111 years.\newlinen=11 years×12 months/yearn = 11 \text{ years} \times 12 \text{ months/year}\newlinen=132 monthsn = 132 \text{ months}
  4. Find Monthly Contribution: Use the formula to find the monthly contribution dd.A=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right)$65,000=d×((1+0.00525)13210.00525)\$65,000 = d \times \left(\frac{(1 + 0.00525)^{132} - 1}{0.00525}\right)
  5. Calculate Value Inside Parentheses: Calculate the value inside the parentheses and the exponent.\newline(1+0.00525)1321(1 + 0.00525)^{132} - 1
  6. Perform Exponentiation: Perform the exponentiation.\newline(1+0.00525)1321.99624(1 + 0.00525)^{132} \approx 1.99624\newline1.9962410.996241.99624 - 1 \approx 0.99624
  7. Divide by Monthly Interest Rate: Divide the result by the monthly interest rate.\newline0.99624/0.00525189.736190.99624 / 0.00525 \approx 189.73619
  8. Solve for 'd': Solve for 'd' by dividing the future value of the account by the result from the previous step.\newline$65,000/189.73619$342.58\$65,000 / 189.73619 \approx \$342.58
  9. Round Monthly Contribution: Round the monthly contribution to the nearest dollar. \newlined$343d \approx \$343 per month

More problems from Compound interest