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Sophia is saving money and plans on making monthly contributions into an account earning an annual interest rate of 6.3% compounded monthly. If Sophia would like to end up with $65,000 after 11 years, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer: ◻

Sophia is saving money and plans on making monthly contributions into an account earning an annual interest rate of 6.3%6.3\% compounded monthly. If Sophia would like to end up with $65,000\$65,000 after 1111 years, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i)A=d\left(\frac{(1+i)^{n}-1}{i}\right)\newlineA=A= the future value of the account after nn periods\newlined=d= the amount invested at the end of each period\newlinei=i= the interest rate per period\newlinen=n= the number of periods\newlineAnswer: ◻

Full solution

Q. Sophia is saving money and plans on making monthly contributions into an account earning an annual interest rate of 6.3%6.3\% compounded monthly. If Sophia would like to end up with $65,000\$65,000 after 1111 years, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i)A=d\left(\frac{(1+i)^{n}-1}{i}\right)\newlineA=A= the future value of the account after nn periods\newlined=d= the amount invested at the end of each period\newlinei=i= the interest rate per period\newlinen=n= the number of periods\newlineAnswer: ◻
  1. Identify Given Values: Identify the given values from the problem.\newlineWe are given:\newlineFuture value of the account, A=$(65,000)A = \$(65,000)\newlineAnnual interest rate, r=6.3%r = 6.3\% or 0.0630.063 (as a decimal)\newlineNumber of years, t=11t = 11\newlineThe interest rate per period (monthly), i=r12i = \frac{r}{12}\newlineThe number of periods, n=t×12n = t \times 12 (since the contributions are monthly)
  2. Convert Annual Interest Rate: Convert the annual interest rate to the monthly interest rate.\newlinei=r12i = \frac{r}{12}\newlinei=0.06312i = \frac{0.063}{12}\newlinei=0.00525i = 0.00525
  3. Calculate Total Periods: Calculate the total number of periods.\newlinen=t×12n = t \times 12\newlinen=11×12n = 11 \times 12\newlinen=132n = 132
  4. Find Monthly Contribution: Use the formula to find the monthly contribution, dd.A=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right)$65,000=d×((1+0.00525)13210.00525)\$65,000 = d \times \left(\frac{(1 + 0.00525)^{132} - 1}{0.00525}\right)
  5. Calculate Value Inside Parentheses: Calculate the value inside the parentheses.\newline(1+i)n1(1 + i)^{n} - 1\newline(1+0.00525)1321(1 + 0.00525)^{132} - 1\newline(1.00525)1321(1.00525)^{132} - 1
  6. Calculate Value of Expression: Calculate the value of the expression (1.00525)1321(1.00525)^{132} - 1. This requires a calculator or a computer to compute. (1.00525)13210.9994(1.00525)^{132} - 1 \approx 0.9994
  7. Substitute Calculated Value: Substitute the calculated value back into the formula.\newline$65,000=d×(0.9994/0.00525)\$65,000 = d \times (0.9994 / 0.00525)
  8. Solve for Monthly Contribution: Solve for dd, the monthly contribution.d=$(65,000)(0.9994/0.00525)d = \frac{\$(65,000)}{(0.9994 / 0.00525)}d$(65,000)0.1902d \approx \frac{\$(65,000)}{0.1902}d$(341.75)d \approx \$(341.75)
  9. Round Monthly Contribution: Round the monthly contribution to the nearest dollar. d$(342)d \approx \$(342)

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