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Solve.\newliney=−3y = -3\newline−2x+8y=−12-2x + 8y = -12\newline(_____, _____)

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Q. Solve.\newliney=−3y = -3\newline−2x+8y=−12-2x + 8y = -12\newline(_____, _____)
  1. Substitute and Simplify: Substitute y=−3y = -3 into the equation −2x+8y=−12-2x + 8y = -12 and then simplify.\newlineSubstitute −3-3 for yy in −2x+8y=−12-2x + 8y = -12.\newline−2x+8(−3)=−12-2x + 8(-3) = -12\newline−2x−24=−12-2x - 24 = -12
  2. Isolate Variable Term: Isolate the variable term to solve for xx.−2x−24=−12-2x - 24 = -12Add 2424 to both sides of the equation.−2x−24+24=−12+24-2x - 24 + 24 = -12 + 24−2x=12-2x = 12
  3. Divide to Find x: Divide both sides by −2-2 to find the value of xx.−2x/−2=12/−2-2x / -2 = 12 / -2x=−6x = -6
  4. Write Solution as Ordered Pair: We have found the values of xx and yy:
    x=−6x = -6
    y=−3y = -3
    Now, we can write the solution as an ordered pair.
    The solution is (−6,−3)(-6, -3).

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