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Solve.\newliney=10y = 10\newline3x+4y=133x + 4y = 13\newline(_____, _____)

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Q. Solve.\newliney=10y = 10\newline3x+4y=133x + 4y = 13\newline(_____, _____)
  1. Substitute y=10y = 10: Substitute y=10y = 10 into the equation 3x+4y=133x + 4y = 13.\newlineSubstitute 1010 for yy in 3x+4y=133x + 4y = 13.\newline3x+4(10)=133x + 4(10) = 13
  2. Simplify the equation: Simplify the equation. 3x+40=133x + 40 = 13
  3. Isolate variable term xx: Isolate the variable term xx.3x+40−40=13−403x + 40 - 40 = 13 - 403x=−273x = -27
  4. Solve for x: Solve for x.\newline3x=−273x = -27\newlinex=−273x = \frac{-27}{3}\newlinex=−9x = -9
  5. Find ordered pair solution: We found:\newlinex=−9x = -9\newliney=10y = 10\newlineWhat is the solution in the form of an ordered pair?\newlineSubstitute x=−9x = -9 and y=10y = 10 into (x,y)(x, y).\newlineThe solution is (−9,10)(-9, 10).

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