Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve using the quadratic formula.\newlines28s5=0s^2 - 8s - 5 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlines=s = _____ or s=s = _____

Full solution

Q. Solve using the quadratic formula.\newlines28s5=0s^2 - 8s - 5 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlines=s = _____ or s=s = _____
  1. Identify values: Identify the values of aa, bb, and cc in the quadratic equation s28s5=0s^2 - 8s - 5 = 0. The standard form of a quadratic equation is ax2+bx+c=0ax^2 + bx + c = 0. By comparing, we find: a=1a = 1 b=8b = -8 c=5c = -5
  2. Substitute into formula: Substitute the values of aa, bb, and cc into the quadratic formula s=b±b24ac2as = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Substitute a=1a = 1, b=8b = -8, and c=5c = -5 into the quadratic formula. s=(8)±(8)241(5)21s = \frac{-(-8) \pm \sqrt{(-8)^2 - 4\cdot 1\cdot (-5)}}{2\cdot 1} <s=8±64+202s = \frac{8 \pm \sqrt{64 + 20}}{2}>
  3. Simplify expression and calculate discriminant: Simplify the expression under the square root and calculate the discriminant.\newline(8)241(5)\sqrt{(-8)^2 - 4\cdot 1\cdot (-5)}\newline= 64+20\sqrt{64 + 20}\newline= 84\sqrt{84}
  4. Simplify quadratic formula: Simplify the quadratic formula with the calculated discriminant.\newlines=8±842s = \frac{8 \pm \sqrt{84}}{2}\newlineSince 84\sqrt{84} simplifies to 2212\sqrt{21}, we can write:\newlines=8±2212s = \frac{8 \pm 2\sqrt{21}}{2}
  5. Calculate approximate decimal values: Simplify the expression by dividing by 22.\newlines=(4±21)s = (4 \pm \sqrt{21})\newlineNow we have two possible solutions for ss:\newlines=4+21s = 4 + \sqrt{21} or s=421s = 4 - \sqrt{21}
  6. Calculate approximate decimal values: Simplify the expression by dividing by 22.\newlines=(4±21)s = (4 \pm \sqrt{21})\newlineNow we have two possible solutions for ss:\newlines=4+21s = 4 + \sqrt{21} or s=421s = 4 - \sqrt{21} Calculate the approximate decimal values of ss if necessary, rounding to the nearest hundredth.\newlines4+4.58s \approx 4 + 4.58 or s44.58s \approx 4 - 4.58\newlines8.58s \approx 8.58 or s0.58s \approx -0.58

More problems from Solve a quadratic equation using the quadratic formula