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Solve using the quadratic formula.\newlines2+4s+4=0s^2 + 4s + 4 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlines=s = _____ or s=s = _____

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Q. Solve using the quadratic formula.\newlines2+4s+4=0s^2 + 4s + 4 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlines=s = _____ or s=s = _____
  1. Quadratic Formula Explanation: The quadratic formula is given by s=−b±b2−4ac2as = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where aa, bb, and cc are the coefficients from the quadratic equation as2+bs+c=0as^2 + bs + c = 0. In this case, a=1a = 1, b=4b = 4, and c=4c = 4.
  2. Calculate Discriminant: First, calculate the discriminant, which is the part under the square root in the quadratic formula: b2−4acb^2 - 4ac. Here, it is 42−4(1)(4)=16−16=04^2 - 4(1)(4) = 16 - 16 = 0.
  3. Real Solution Determination: Since the discriminant is 00, there is only one real solution to the equation. The square root of the discriminant is 0=0\sqrt{0} = 0.
  4. Apply Quadratic Formula: Now, apply the quadratic formula with the calculated values: s=−4±02×1=−42=−2s = \frac{-4 \pm 0}{2 \times 1} = \frac{-4}{2} = -2.
  5. Final Solution: The solution to the equation s2+4s+4=0s^2 + 4s + 4 = 0 is s=−2s = -2. Since the discriminant was 00, there is only one unique solution, which is a repeated root.

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