Solve using the quadratic formula.j2−5j+1=0Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.j= _____ or j= _____
Q. Solve using the quadratic formula.j2−5j+1=0Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.j= _____ or j= _____
Quadratic Formula Definition: The quadratic formula is given by j=2a−b±b2−4ac, where a, b, and c are the coefficients from the quadratic equation in the form aj2+bj+c=0. For our equation, a=1, b=−5, and c=1.
Calculate Discriminant: First, calculate the discriminant, which is the part under the square root in the quadratic formula: b2−4ac. For our equation, this is (−5)2−4(1)(1)=25−4=21.
Apply Quadratic Formula: Now, apply the quadratic formula with the values of a, b, and c. We have j=2×1−(−5)±21=25±21.
Simplify Solutions: Since 21 cannot be simplified into a perfect square, we will leave it as is under the square root. The two solutions for j are j=25+21 and j=25−21.
Calculate Decimal Approximations: To express the solutions as decimals rounded to the nearest hundredth, we calculate each one. For j=25+21, the approximate value is 25+4.58≈29.58≈4.79. For j=25−21, the approximate value is 25−4.58≈20.42≈0.21.
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