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Solve using the quadratic formula.\newline8y2−6y−1=08y^2 - 6y - 1 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newliney=y = _____ or y=y = _____

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Q. Solve using the quadratic formula.\newline8y2−6y−1=08y^2 - 6y - 1 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newliney=y = _____ or y=y = _____
  1. Identify values of aa, bb, and cc: Identify values of aa, bb, and cc from the equation 8y2−6y−1=08y^2 − 6y − 1 = 0.\newlinea=8a = 8, b=−6b = -6, c=−1c = -1.
  2. Plug values into quadratic formula: Plug aa, bb, and cc into the quadratic formula y=−b±b2−4ac2ay = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.\newliney=−(−6)±(−6)2−4⋅8⋅(−1)2⋅8.y = \frac{-(-6) \pm \sqrt{(-6)^2 - 4\cdot8\cdot(-1)}}{2\cdot8}.
  3. Simplify equation: Simplify inside the square root and the constants outside.\newliney=6±36+3216y = \frac{6 \pm \sqrt{36 + 32}}{16}.
  4. Add numbers inside square root: Add the numbers inside the square root.\newliney=6±6816y = \frac{6 \pm \sqrt{68}}{16}.
  5. Calculate possible solutions: Simplify the square root (if possible) and calculate the two possible solutions for yy.\newliney=6±6816y = \frac{6 \pm \sqrt{68}}{16}.\newliney=6+6816y = \frac{6 + \sqrt{68}}{16} or y=6−6816y = \frac{6 - \sqrt{68}}{16}.
  6. Round values if necessary: Round the values of yy to the nearest hundredth, if necessary.y≈(6+8.25)/16y \approx (6 + 8.25) / 16 or y≈(6−8.25)/16y \approx (6 - 8.25) / 16.y≈14.25/16y \approx 14.25 / 16 or y≈−2.25/16y \approx -2.25 / 16.y≈0.89y \approx 0.89 or y≈−0.14y \approx -0.14.

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