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Solve using the quadratic formula.\newline3g28g+4=03g^2 - 8g + 4 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlineg=g = _____ or g=g = _____

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Q. Solve using the quadratic formula.\newline3g28g+4=03g^2 - 8g + 4 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlineg=g = _____ or g=g = _____
  1. Quadratic Formula Definition: The quadratic formula is given by g=b±b24ac2ag = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where aa, bb, and cc are the coefficients of the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0. For the equation 3g28g+4=03g^2 - 8g + 4 = 0, a=3a = 3, b=8b = -8, and c=4c = 4.
  2. Calculate Discriminant: First, calculate the discriminant, which is the part under the square root in the quadratic formula: b24acb^2 - 4ac. Here, it is (8)24(3)(4)(-8)^2 - 4(3)(4).
  3. Discriminant Calculation: Perform the calculation: (8)24(3)(4)=6448=16(-8)^2 - 4(3)(4) = 64 - 48 = 16.
  4. Apply Quadratic Formula: Now, apply the quadratic formula with the calculated discriminant. The solutions for gg will be g=(8)±162×3g = \frac{-(-8) \pm \sqrt{16}}{2 \times 3}.
  5. Simplify Equation: Simplify the equation: g=8±166g = \frac{8 \pm \sqrt{16}}{6}.
  6. Solve for Solutions: Since 16=4\sqrt{16} = 4, the equation becomes g=(8±4)6g = \frac{(8 \pm 4)}{6}.
  7. Calculate Solutions: Now, solve for the two possible values of gg: g=8+46g = \frac{8 + 4}{6} and g=846g = \frac{8 - 4}{6}.
  8. Simplify Fractions: Calculate the two solutions: g=126g = \frac{12}{6} and g=46.g = \frac{4}{6}.
  9. Simplify Fractions: Calculate the two solutions: g=126g = \frac{12}{6} and g=46g = \frac{4}{6}.Simplify the fractions: g=2g = 2 and g=23g = \frac{2}{3}.

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