Solve using augmented matrices. y = 10 9x + 10y = 10 (_____, _____)

Write Equations as Matrix: Write the system of equations as an augmented matrix. [[1, 0, 10], [9, 10, 10]]Modify Second Equation: Since the first equation is already solved for y, we can use it to modify the second equation. Subtract 10 times the first row from the second row to eliminate the y-term. New second row: [9, 10, 10] - 10*[1, 0, 10] = [9, 10, 10] - [10, 0, 100] = [-1, 10, -90]Replace Second Row: Replace the second row with the new values. The augmented matrix now looks like this: [[1, 0, 10], [-1, 10, -90]]Add First Row: Add the first row to the second row to get the x-term alone. New second row: [-1, 10, -90] + [1, 0, 10] = [0, 10, -80]Divide Second Row: Divide the second row by 10 to solve for x. New second row: [0, 10, -80] / 10 = [0, 1, -8]Final Solution: Now we have the second equation in the form of x = -8. So the solution to the system is (x, y) = (-8, 10).

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Solve using augmented matrices. $\newline$ $y = 10$ $\newline$ $9x + 10y = 10$ $\newline$ (_, _)

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Q. Solve using augmented matrices.

\newline

y = 10

\newline

9x + 10y = 10

\newline

(_____, _____)

Write Equations as Matrix: Write the system of equations as an augmented matrix. $\left[\begin{array}{cc|c} 1 & 0 & 10 \ 9 & 10 & 10 \end{array}\right]$
Modify Second Equation: Since the first equation is already solved for $y$ , we can use it to modify the second equation. $\newline$ Subtract $10$ times the first row from the second row to eliminate the $y$ -term. $\newline$ New second row: $[9, 10, 10] - 10\times[1, 0, 10] = [9, 10, 10] - [10, 0, 100] = [-1, 10, -90]$
Replace Second Row: Replace the second row with the new values. $\newline$ The augmented matrix now looks like this: $\newline$ \left[\begin{array}{ccc}$\newline1 & 0 & 10 (\newline$-1 & 10 & -90 $\newline$ \end{array}\right]\)
Add First Row: Add the first row to the second row to get the $x$ -term alone. $\newline$ New second row: [\(-1, $10$ , $-90$ \] + [\(1, $0$ , $10$ \] = [\(0, $10$ , $-80$ \]
Divide Second Row: Divide the second row by $10$ to solve for $x$ . $\newline$ New second row: $[0, 10, -80] / 10 = [0, 1, -8]$
Final Solution: Now we have the second equation in the form of $x = -8$ . So the solution to the system is $(x, y) = (-8, 10)$ .