Solve using augmented matrices. –x + 3y = 5 y = 4 (_____, _____)

Convert Equations to Matrix: Convert the system of equations into an augmented matrix: –x + 3y = 5 y = 4 The matrix is: [ -1 3 | 5 ] [ 0 1 | 4 ] Eliminate Y-Term: Since the second row already shows y = 4, we use this to eliminate the y-term from the first row. Multiply the second row by -3 and add it to the first row: (-3) * [0 1 | 4] + [-1 3 | 5] = [-1 0 | -7] Final Solution: Now, the matrix is in reduced row echelon form: [-1 0 | -7] [ 0 1 | 4] This means x = -7 and y = 4.

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Solve using augmented matrices. $\newline$ $-x + 3y = 5$ $\newline$ $y = 4$ $\newline$ $(\_, \_)$

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Q. Solve using augmented matrices.

\newline

-x + 3y = 5

\newline

y = 4

\newline

(\_, \_)

Convert Equations to Matrix: Convert the system of equations into an augmented matrix: $\newline$ $-x + 3y = 5$ $\newline$ $y = 4$ $\newline$ The matrix is: $\newline$ $\begin{bmatrix} -1 & 3 | & 5 \ 0 & 1 | & 4 \end{bmatrix}$
Eliminate Y-Term: Since the second row already shows $y = 4$ , we use this to eliminate the $y$ -term from the first row. Multiply the second row by $-3$ and add it to the first row: $(-3) \times [0 1 | 4] + [-1 3 | 5] = [-1 0 | -7]$
Final Solution: Now, the matrix is in reduced row echelon form: $\newline$ \begin{array}{cc|c} -1 & 0 & -7 \ 0 & 1 & 4 \end{array} $\newline$ This means $x = -7$ and $y = 4$ .