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Solve the system of equations.\newliney=x2+21x4y = x^2 + 21x - 4\newliney=22x+26y = 22x + 26\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

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Q. Solve the system of equations.\newliney=x2+21x4y = x^2 + 21x - 4\newliney=22x+26y = 22x + 26\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Set Equations Equal: Set the two equations equal to each other since they both equal yy. This gives us x2+21x4=22x+26x^2 + 21x - 4 = 22x + 26.
  2. Rearrange and Simplify: Rearrange the equation to set it to zero. Subtract 22x+2622x + 26 from both sides to get x2+21x422x26=0x^2 + 21x - 4 - 22x - 26 = 0. This simplifies to x2x30=0x^2 - x - 30 = 0.
  3. Factor Quadratic Equation: Factor the quadratic equation x2x30x^2 - x - 30. The factors of 30-30 that add up to 1-1 are 6-6 and +5+5. So the equation factors to (x6)(x+5)=0(x - 6)(x + 5) = 0.
  4. Solve for x: Solve for x by setting each factor equal to zero. This gives us x6=0x - 6 = 0 and x+5=0x + 5 = 0. Solving these gives us x=6x = 6 and x=5x = -5.
  5. Substitute x Values: Substitute x=6x = 6 into one of the original equations to find the corresponding yy value. Using y=22x+26y = 22x + 26, we get y=22(6)+26y = 22(6) + 26, which simplifies to y=132+26y = 132 + 26, giving us y=158y = 158.
  6. Find Corresponding y Values: Substitute x=5x = -5 into one of the original equations to find the corresponding y value. Using y=22x+26y = 22x + 26, we get y=22(5)+26y = 22(-5) + 26, which simplifies to y=110+26y = -110 + 26, giving us y=84y = -84.

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