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Solve the system of equations.\newliney=45x+46y = 45x + 46\newliney=x2+38x+28y = x^2 + 38x + 28\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

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Q. Solve the system of equations.\newliney=45x+46y = 45x + 46\newliney=x2+38x+28y = x^2 + 38x + 28\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Substitute yy in second equation: Substitute yy from the first equation into the second equation. Since y=45x+46y = 45x + 46, we can replace yy in the second equation with 45x+4645x + 46. This gives us the equation 45x+46=x2+38x+2845x + 46 = x^2 + 38x + 28.
  2. Rearrange and solve for x: Rearrange the equation to set it to zero and solve for x. This means we subtract 45x45x and 4646 from both sides to get 0=x2+38x+2845x460 = x^2 + 38x + 28 - 45x - 46. Simplifying this gives us 0=x27x180 = x^2 - 7x - 18.
  3. Factor quadratic equation: Factor the quadratic equation x27x18x^2 - 7x - 18. The factors of 18-18 that add up to 7-7 are 9-9 and +2+2. So the factored form is (x9)(x+2)=0(x - 9)(x + 2) = 0.
  4. Solve for x: Solve for x by setting each factor equal to zero. This gives us two solutions: x9=0x - 9 = 0, which gives x=9x = 9, and x+2=0x + 2 = 0, which gives x=2x = -2.
  5. Substitute x=9x=9 for yy: Substitute x=9x = 9 into the first equation y=45x+46y = 45x + 46 to find the corresponding value of yy. This gives us y=45(9)+46y = 45(9) + 46, which simplifies to y=405+46y = 405 + 46, and thus y=451y = 451.
  6. Substitute x=2x=-2 for yy: Substitute x=2x = -2 into the first equation y=45x+46y = 45x + 46 to find the corresponding value of yy. This gives us y=45(2)+46y = 45(-2) + 46, which simplifies to y=90+46y = -90 + 46, and thus y=44y = -44.

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