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Solve the system of equations.\newliney=35x29y = 35x - 29\newliney=x2+22x+7y = x^2 + 22x + 7\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

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Q. Solve the system of equations.\newliney=35x29y = 35x - 29\newliney=x2+22x+7y = x^2 + 22x + 7\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Substitute y Equation: Substitute yy from the first equation into the second equation. Since y=35x29y = 35x - 29 and y=x2+22x+7y = x^2 + 22x + 7, we can set them equal to each other: 35x29=x2+22x+735x - 29 = x^2 + 22x + 7.
  2. Rearrange and Solve for x: Rearrange the equation to set it to zero and solve for x: x2+22x+735x+29=0x^2 + 22x + 7 - 35x + 29 = 0, which simplifies to x213x+36=0x^2 - 13x + 36 = 0.
  3. Factor Quadratic Equation: Factor the quadratic equation: (x4)(x9)=0(x - 4)(x - 9) = 0.
  4. Solve for x: Solve for x by setting each factor equal to zero: x4=0x - 4 = 0 or x9=0x - 9 = 0. This gives us x=4x = 4 or x=9x = 9.
  5. Substitute x=4x = 4: Substitute x=4x = 4 into the first equation y=35x29y = 35x - 29 to find the corresponding value of yy: y=35(4)29y = 35(4) - 29, which simplifies to y=14029y = 140 - 29, so y=111y = 111.
  6. Substitute x=9x = 9: Substitute x=9x = 9 into the first equation y=35x29y = 35x - 29 to find the corresponding value of yy: y=35(9)29y = 35(9) - 29, which simplifies to y=31529y = 315 - 29, so y=286y = 286.
  7. Write Coordinate Points: Write the solution as coordinate points. The coordinate points are (4,111)(4, 111) and (9,286)(9, 286).

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