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Solve the system of equations.\newliney=32x+20y = -32x + 20\newliney=x237x16y = x^2 - 37x - 16\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

Full solution

Q. Solve the system of equations.\newliney=32x+20y = -32x + 20\newliney=x237x16y = x^2 - 37x - 16\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Substitute yy into second equation: Substitute yy from the first equation into the second equation to find xx. This gives us 32x+20=x237x16-32x + 20 = x^2 - 37x - 16.
  2. Rearrange to set to zero: Rearrange the equation to set it to zero: x237x+32x1620=0x^2 - 37x + 32x - 16 - 20 = 0. This simplifies to x25x36=0x^2 - 5x - 36 = 0.
  3. Factor the quadratic equation: Factor the quadratic equation: (x9)(x+4)=0(x - 9)(x + 4) = 0.
  4. Solve for x: Solve for x by setting each factor equal to zero: x9=0x - 9 = 0 or x+4=0x + 4 = 0. This gives us x=9x = 9 or x=4x = -4.
  5. Substitute x=9x=9 into first equation: Substitute x=9x = 9 into the first equation y=32x+20y = -32x + 20 to find yy. This gives us y=32(9)+20y = -32(9) + 20.
  6. Calculate yy when x=9x=9: Calculate yy when x=9x = 9: y=288+20y = -288 + 20, which simplifies to y=268y = -268.
  7. Substitute x=4x=-4 into first equation: Substitute x=4x = -4 into the first equation y=32x+20y = -32x + 20 to find yy. This gives us y=32(4)+20y = -32(-4) + 20.
  8. Calculate yy when x=4x=-4: Calculate yy when x=4x = -4: y=128+20y = 128 + 20, which simplifies to y=148y = 148.

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