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Solve the system of equations.\newliney=12x37y = 12x - 37\newliney=x2+2x21y = x^2 + 2x - 21\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

Full solution

Q. Solve the system of equations.\newliney=12x37y = 12x - 37\newliney=x2+2x21y = x^2 + 2x - 21\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Substitute yy into second equation: Substitute yy from the first equation into the second equation. Since y=12x37y = 12x - 37 and y=x2+2x21y = x^2 + 2x - 21, we can set them equal to each other: 12x37=x2+2x2112x - 37 = x^2 + 2x - 21.
  2. Rearrange and solve for x: Rearrange the equation to set it to zero and solve for xx: x2+2x2112x+37=0x^2 + 2x - 21 - 12x + 37 = 0, which simplifies to x210x+16=0x^2 - 10x + 16 = 0.
  3. Factor the quadratic equation: Factor the quadratic equation: (x8)(x2)=0(x - 8)(x - 2) = 0.
  4. Solve for x: Solve for x by setting each factor equal to zero: x8=0x - 8 = 0 or x2=0x - 2 = 0. This gives us x=8x = 8 or x=2x = 2.
  5. Substitute x=8x=8 to find yy: Substitute x=8x = 8 into the first equation to find yy: y=12(8)37y = 12(8) - 37, which simplifies to y=9637y = 96 - 37, so y=59y = 59.
  6. Substitute x=2x=2 to find yy: Substitute x=2x = 2 into the first equation to find yy: y=12(2)37y = 12(2) - 37, which simplifies to y=2437y = 24 - 37, so y=13y = -13.

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