Solve the quadratic by factoring. x^(2)-4x-4=8 Answer: x=

Rewrite in standard form: Rewrite the equation in standard form by moving all terms to one side. x^2 - 4x - 4 = 8 Subtract 8 from both sides to get: x^2 - 4x - 12 = 0Factor the quadratic: Factor the quadratic equation. We need to find two numbers that multiply to -12 and add up to -4. The numbers -6 and +2 satisfy these conditions because: (-6) * (+2) = -12 (-6) + (+2) = -4 So we can factor the quadratic as: (x - 6)(x + 2) = 0Solve for x: Solve for x by setting each factor equal to zero. x - 6 = 0 or x + 2 = 0 Solving each equation gives us: x = 6 or x = -2

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Algebra 1

Factor quadratics with leading coefficient 1

Full solution

Q. Solve the quadratic by factoring.

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x^{2}-4 x-4=8

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Answer:

x=

Rewrite in standard form: Rewrite the equation in standard form by moving all terms to one side. $\newline$ $x^2 - 4x - 4 = 8$ $\newline$ Subtract $8$ from both sides to get: $\newline$ $x^2 - 4x - 12 = 0$
Factor the quadratic: Factor the quadratic equation. $\newline$ We need to find two numbers that multiply to $-12$ and add up to $-4$ . $\newline$ The numbers $-6$ and $+2$ satisfy these conditions because: $\newline$ $(-6) \times (+2) = -12$ $\newline$ $(-6) + (+2) = -4$ $\newline$ So we can factor the quadratic as: $\newline$ $(x - 6)(x + 2) = 0$
Solve for x: Solve for x by setting each factor equal to zero. $\newline$ $x - 6 = 0$ or $x + 2 = 0$ $\newline$ Solving each equation gives us: $\newline$ $x = 6$ or $x = -2$