Solve the quadratic by factoring. x^(2)+17 x-6=9x+3 Answer: x=

Write Standard Form: Write the quadratic equation in standard form by moving all terms to one side of the equation. x^2 + 17x - 6 - 9x - 3 = 0 Combine like terms. x^2 + 8x - 9 = 0Factor Quadratic Equation: Factor the quadratic equation. We need to find two numbers that multiply to -9 and add up to 8. The numbers 9 and -1 satisfy these conditions because 9 * -1 = -9 and 9 + (-1) = 8. So we can write the factored form as: (x + 9)(x - 1) = 0Solve for x: Solve for x by setting each factor equal to zero. x + 9 = 0 or x - 1 = 0 Solve each equation for x. x = -9 or x = 1

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Algebra 1

Factor quadratics with leading coefficient 1

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Q. Solve the quadratic by factoring.

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x^{2}+17 x-6=9 x+3

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Answer:

x=

Write Standard Form: Write the quadratic equation in standard form by moving all terms to one side of the equation. $\newline$ $x^2 + 17x - 6 - 9x - 3 = 0$ $\newline$ Combine like terms. $\newline$ $x^2 + 8x - 9 = 0$
Factor Quadratic Equation: Factor the quadratic equation. $\newline$ We need to find two numbers that multiply to $-9$ and add up to $8$ . $\newline$ The numbers $9$ and $-1$ satisfy these conditions because $9 \times -1 = -9$ and $9 + (-1) = 8$ . $\newline$ So we can write the factored form as: $\newline$ $(x + 9)(x - 1) = 0$
Solve for x: Solve for x by setting each factor equal to zero. $\newline$ $x + 9 = 0$ or $x - 1 = 0$ $\newline$ Solve each equation for x. $\newline$ $x = -9$ or $x = 1$