Solve the quadratic by factoring. 5x^(2)+4x+2=3 Answer: x=

Write Standard Form: Write the quadratic equation in standard form. Subtract 3 from both sides of the equation to get the quadratic in standard form. 5x^2 + 4x + 2 = 3 5x^2 + 4x + 2 - 3 = 0 5x^2 + 4x - 1 = 0Identify a, b, c: Identify a, b, and c in the quadratic equation. Compare 5x^2 + 4x - 1 with ax^2 + bx + c. a = 5 b = 4 c = -1Find Multiplying Numbers: Find two numbers that multiply to a*c (5*-1 = -5) and add up to b (4). Unfortunately, there are no two integers that multiply to -5 and add up to 4. This means we cannot factor the quadratic equation using integers. We would need to use other methods such as completing the square or the quadratic formula to solve this equation.

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Algebra 1

Factor quadratics with other leading coefficients

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Q. Solve the quadratic by factoring.

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5 x^{2}+4 x+2=3

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Answer:

x=

Write Standard Form: Write the quadratic equation in standard form. $\newline$ Subtract $3$ from both sides of the equation to get the quadratic in standard form. $\newline$ $5x^2 + 4x + 2 = 3$ $\newline$ $5x^2 + 4x + 2 - 3 = 0$ $\newline$ $5x^2 + 4x - 1 = 0$
Identify $a, b, c$ : Identify $a, b,$ and $c$ in the quadratic equation. $\newline$ Compare $5x^2 + 4x - 1$ with $ax^2 + bx + c$ . $\newline$ $a = 5$ $\newline$ $b = 4$ $\newline$ $c = -1$
Find Multiplying Numbers: Find two numbers that multiply to $a*c$ ( $5*-1 = -5$ ) and add up to $b$ ( $4$ ). $\newline$ Unfortunately, there are no two integers that multiply to $-5$ and add up to $4$ . This means we cannot factor the quadratic equation using integers. We would need to use other methods such as completing the square or the quadratic formula to solve this equation.