Solve the quadratic by factoring. 5x^(2)-21 x-5=3x Answer: x=

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Solve the quadratic by factoring.  5x^(2)-21 x-5=3x Answer:  x=

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Move Terms to One Side: Move all terms to one side of the equation to set the equation to zero. Subtract 3x from both sides of the equation 5x^2 - 21x - 5 = 3x. 5x^2 - 21x - 5 - 3x = 3x - 3x 5x^2 - 24x - 5 = 0Identify a, b, c: Identify a, b, and c in the quadratic equation ax^2 + bx + c = 0. For the equation 5x^2 - 24x - 5 = 0, a = 5, b = -24, and c = -5.Find Two Numbers: Find two numbers that multiply to a*c (5*-5 = -25) and add up to b (-24). The numbers that satisfy these conditions are -25 and 1 because: -25 * 1 = -25 (which is a*c) -25 + 1 = -24 (which is b)Split Middle Term: Rewrite the equation by splitting the middle term using the two numbers found in Step 3. 5x^2 - 25x + x - 5 = 0Factor by Grouping: Factor by grouping. Group the first two terms and the last two terms: (5x^2 - 25x) + (x - 5) Factor out the greatest common factor from each group: 5x(x - 5) + 1(x - 5)Factor Common Binomial: Factor out the common binomial factor. The common binomial factor is (x - 5). 5x(x - 5) + 1(x - 5) = (5x + 1)(x - 5)Set Factors Equal: Set each factor equal to zero and solve for x. 5x + 1 = 0 and x - 5 = 0 For 5x + 1 = 0: Subtract 1 from both sides and then divide by 5. 5x = -1 x = -1/5 For x - 5 = 0: Add 5 to both sides. x = 5

Solve the quadratic by factoring. $\newline$ $5 x^{2}-21 x-5=3 x$ $\newline$ Answer: $x=$

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Solve the quadratic by factoring.\newline5x2−21x−5=3x 5 x^{2}-21 x-5=3 x 5x2−21x−5=3x\newlineAnswer: x= x= x=

Solve the quadratic by factoring. $\newline$ $5 x^{2}-21 x-5=3 x$ $\newline$ Answer: $x=$